Conservation of Momentum and Collisions

Set two carts' masses, speeds, and elasticity, then collide them. Momentum is conserved in every collision, elastic or inelastic, but kinetic energy is lost unless the collision is perfectly elastic.

Set each cart's mass and speed, choose how bouncy the hit is with the elasticity slider (e), then press Play. Momentum is conserved in every collision; kinetic energy is only conserved when e = 1.

Two carts on a fixed track. Cart A (blue) and cart B (amber) roll toward each other and collide. A green total-momentum arrow at the centre stays the same length before and after the collision.Each cart carries a momentum arrow proportional to its mass times velocity; a central green arrow shows the total momentum, which does not change when the carts collide.total p 0A2 kgp 6B2 kgp -6

Press Play. The carts roll together, collide once, then leave at the speeds physics predicts.

Momentum conserved

Total p before = 0 kg·m/s, total p after = 0 kg·m/s. They are equal for every value of e.

Elastic: kinetic energy conserved

KE before = KE after = 18 J. No energy is lost.

Total momentum (kg·m/s)unchanged
before0
after0

Equal and opposite momenta, so the total is zero before and after.

Kinetic energy (J)unchanged
before18
after18
v beforev afterp after
Cart A (2 kg)3-3-6
Cart B (2 kg)-336
Collision type

p = m·v (cart A, before)2 × 3 = 6

p = m·v (cart B, before)2 × -3 = -6

Total p0 kg·m/s

Impulse on B = m_B(v_B - u_B)12 kg·m/s

Impulse on A = m_A(v_A - u_A)-12 kg·m/s

The two impulses are equal and opposite, so the total change in momentum is zero.

The after-velocities come from the 1D collision equations with coefficient of restitution e (from the site's unit-tested physics library), which conserve total momentum for every e and conserve kinetic energy only at e = 1. Impulse is shown as each cart's measured change in momentum, m(v - u), not from a fabricated contact force.

Ready. Total momentum 0 kilogram metres per second. Press Play.

Two carts crash. One sticks to the other, they crumple, they slow down. Surely something is lost? Something is: kinetic energy. But one quantity survives every crash untouched, whether the carts bounce cleanly apart or jam together into one mangled lump: their total momentum. Roll the carts together in the lab above and watch the green total-momentum arrow. It is the same length before and after the hit, every single time. That is the law this lesson is about.

What is momentum? The p = mv formula

Momentum measures how much motion an object carries: how hard it is to stop. It depends on both how heavy the object is and how fast it is going, combined in one short formula.

momentum: p = m × v   (mass in kg, velocity in m/s, so p is in kg·m/s)

A loaded truck rolling slowly can carry more momentum than a fast bicycle, because its huge mass outweighs the bicycle’s higher speed. Momentum is a vector: it has direction. If you call rightward positive, then a cart moving left has negative momentum, and you must keep the sign when you add momenta together. That sign is why the total momentum arrow in the lab can point left, point right, or shrink to nothing when two equal carts run head-on.

A quick calculation: a 2 kg cart moving at 3 m/s has p = 2 × 3 = 6 kg·m/s. Double its speed to 6 m/s and its momentum doubles to 12 kg·m/s. Send an identical cart the other way at 3 m/s and its momentum is -6 kg·m/s, the exact opposite.

The law of conservation of momentum

Set two carts moving, let them collide, and add up the momentum before and after. In an isolated system (no outside push or pull like friction or a hand) the answer never changes:

total p before = total p after m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Here u is a velocity before the collision and v is the velocity after. This is the law of conservation of momentum, and it holds for every collision: gentle or violent, bouncy or sticky. In the lab, the “Momentum before” and “Momentum after” readouts match to the last digit, and the two momentum bars are always the same height.

Elastic collisions: momentum and kinetic energy both conserved

A perfectly elastic collision is the bounciest kind: the objects rebound with no loss of kinetic energy at all. In the lab this is the elasticity slider at e = 1. Two things are conserved here, not one: total momentum and total kinetic energy.

kinetic energy: KE = ½ × m × v²

Real-world collisions are almost never perfectly elastic (steel ball bearings and billiard balls come close), but the elastic case is the clean benchmark. The most famous example is a Newton’s cradle: one ball swings in, one ball swings out, at the same speed.

That result surprises people who expect the heavier-looking, still-moving cart A to plough through. With equal masses and a perfect bounce, cart A hands over all of its momentum and stops dead. Following the preset, the total momentum stayed 8 kg·m/s for the 2 kg cart at 4 m/s, and the total kinetic energy stayed 16 J: both conserved.

Inelastic and perfectly inelastic collisions: energy is lost

In an inelastic collision the objects do not bounce back perfectly. Some kinetic energy is converted into heat, sound, and permanent deformation (the crumple of a car bumper). Momentum is still conserved, but kinetic energy is not. On the slider this is any e less than 1.

The extreme case is a perfectly inelastic collision, e = 0, where the objects stick together and move off as one. This loses the largest possible fraction of kinetic energy while still conserving momentum. Because the two bodies share a single final velocity, you can find it directly:

perfectly inelastic (stick): v = (m₁u₁ + m₂u₂) / (m₁ + m₂)

Worked example: a 2 kg cart at 4 m/s hits a stationary 2 kg cart with e = 0. They move off together at v = (2×4 + 2×0) / (2 + 2) = 2 m/s. Total momentum is 8 kg·m/s before and after, so momentum is conserved. But kinetic energy falls from ½ × 2 × 4² = 16 J to ½ × 4 × 2² = 8 J: half the energy is gone, turned into sound and deformation. Set exactly this up in the lab and the KE-after bar drops to half height while the momentum bars stay level.

Elastic vs inelastic collisions: the one real difference

It is tempting to think elastic and inelastic collisions differ in whether momentum is conserved. They do not. Momentum is conserved in both. The single real difference is kinetic energy.

Collision typeeMomentumKinetic energy
Perfectly elastic1ConservedConserved
Inelasticbetween 0 and 1ConservedSome lost
Perfectly inelastic (stick)0ConservedMost lost

The coefficient of restitution e ties them together. It is the ratio of the separation speed after the collision to the approach speed before, a number from 0 (stick) to 1 (perfect bounce). Slide e from 1 down to 0 in the lab and watch the momentum bars refuse to change while the KE-after bar shrinks steadily. That contrast is the whole idea in one picture.

Impulse: how a force changes momentum

To change an object’s momentum you have to push on it for some time. That combined effect, force acting over time, is called impulse, and it equals the change in momentum. This is the impulse-momentum theorem:

impulse: J = F × t = Δp = m × v - m × u

Worked example: hit a 0.5 kg ball with an average force of 20 N for 0.1 s. The impulse is J = 20 × 0.1 = 2 N·s, which equals the ball’s change in momentum, so its momentum rises by 2 kg·m/s. Starting from rest, that is a final speed of 4 m/s.

Impulse is also why momentum is conserved in a collision. During contact the two carts push on each other with equal and opposite forces (Newton’s third law) for the same short time, so they receive equal and opposite impulses. One cart’s momentum gain exactly matches the other’s loss, and the total does not budge. The lab shows this directly: the “Impulse on B” and “Impulse on A” readouts are always equal in size and opposite in sign.

Common momentum mistakes

Keep exploring

The equal-and-opposite forces behind conservation are Newton’s third law, and the force-over-time idea in impulse is the same F that drives the F = ma calculator. See where kinetic energy actually goes when it is “lost” to rubbing surfaces in friction, and turn the carts’ constant-velocity travel before and after the hit into slopes on a motion graph.

Frequently asked questions

What is momentum in physics?
Momentum is a measure of mass in motion: how hard it is to stop a moving object. It is written p and defined by the formula p = m×v, where m is mass in kilograms and v is velocity in metres per second, giving units of kg·m/s. Momentum is a vector, so its direction matters: a cart moving left has the opposite sign of an identical cart moving right. Doubling either the mass or the speed doubles the momentum.
What is the formula for momentum?
The momentum formula is p = m×v (momentum equals mass times velocity). Mass is in kilograms and velocity is in metres per second, so momentum is measured in kg·m/s. Because velocity is a vector, momentum has direction too; you must keep track of the sign (for example, take rightward as positive and leftward as negative) when you add up the momentum of several objects.
Is momentum conserved in an inelastic collision?
Yes. Total momentum is conserved in every collision in an isolated system, elastic or inelastic, including a perfectly inelastic one where the objects stick together. What is NOT conserved in an inelastic collision is kinetic energy: some of it is converted to heat, sound, and permanent deformation. In the lab above, set the elasticity to 0 and you will see the momentum-before and momentum-after readouts stay equal while the kinetic-energy readout drops.
What is the difference between an elastic and an inelastic collision?
In both kinds of collision total momentum is conserved. The difference is kinetic energy. In an elastic collision (coefficient of restitution e = 1) the objects bounce apart and total kinetic energy is also conserved. In an inelastic collision (e less than 1) some kinetic energy is lost to heat, sound, and deformation; in a perfectly inelastic collision (e = 0) the objects stick together and the greatest fraction of kinetic energy is lost. So the single real difference is whether kinetic energy is conserved, not momentum.
Why is momentum always conserved in a collision?
During a collision the two objects push on each other with equal and opposite forces (Newton's third law) for the same short time, so they receive equal and opposite impulses. One object's momentum increase exactly matches the other's decrease, so the total does not change. As long as no outside force acts on the system, total momentum before the collision equals total momentum after it.
What is the coefficient of restitution?
The coefficient of restitution, e, is a number from 0 to 1 that measures how bouncy a collision is: it is the ratio of the relative speed after the collision to the relative speed before. e = 1 is a perfectly elastic collision (no kinetic energy lost), e = 0 is a perfectly inelastic collision (the objects stick together), and values in between are ordinary inelastic collisions. Momentum is conserved for every value of e; only at e = 1 is kinetic energy also conserved.

Sources

Last reviewed: 2026-07-10

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