Stoichiometry is recipe math
A balanced chemical equation is a recipe. A cookie recipe might say “2 cups flour make 1 dozen cookies”; the equation 2 H₂ + O₂ → 2 H₂O says “2 moles of hydrogen and 1 mole of oxygen make 2 moles of water.” Stoichiometry is just using those numbers to figure out how much — how much product you can make, or how much reactant you need. The catch: the recipe only works once the equation is balanced, because the coefficients are the amounts. The tool above runs every step for you, and it’s free to embed on your own site or LMS.
Coefficients are the mole ratio
The single most useful idea in this lesson: the coefficients are the mole ratio. They tell you the proportion in which substances react and form, counted in moles. From 2 H₂ + O₂ → 2 H₂O you can read off several ratios at once:
- H₂O to H₂ is 2 : 2 (so 1 : 1)
- H₂ to O₂ is 2 : 1
- O₂ to H₂O is 1 : 2
To “hop” from a known amount of one substance to an unknown amount of another, multiply by the matching ratio: moles of want = moles of have × (coefficient of want ÷ coefficient of have). Coefficients count particles, so the ratios are always in moles — never in grams.
Grams and moles: convert with molar mass
Lab measurements come in grams, but the ratio only speaks moles, so you translate with molar mass (grams per mole), summed from atomic masses on the periodic table. Going from grams to moles you divide by molar mass; going back from moles to grams you multiply. Building formulas and counting their atoms in the molecule builder is good practice for getting those molar masses right.
A worked example
How much water forms from 4.000 g of H₂ in 2 H₂ + O₂ → 2 H₂O?
- Grams → moles. The molar mass of H₂ is about 2.016 g/mol, so 4.000 g ÷ 2.016 g/mol = 1.984 mol H₂.
- Mole ratio. From the coefficients, H₂O : H₂ is 2 : 2 = 1, so 1.984 mol × (2 ÷ 2) = 1.984 mol H₂O.
- Moles → grams. The molar mass of H₂O is about 18.015 g/mol, so 1.984 mol × 18.015 g/mol ≈ 35.744 g H₂O.
Only step 2 crosses from one substance to another — that’s the mole ratio doing its job. Steps 1 and 3 are pure unit conversion within a single substance.
The road map to remember
Every grams-to-grams problem follows the same path:
grams (given) → moles (given) → moles (find) → grams (find)
Divide by molar mass to enter the world of moles, multiply by the mole ratio to move between substances, then multiply by molar mass to leave it again. Try different reactions and amounts in the tool above and watch the same three steps repeat every time.