Interactive Ohm's Law Calculator

Set any two of voltage, current, and resistance and watch the third solve itself with V = I × R. A live circuit lights a bulb whose brightness tracks the power.

Solve for
VR3.6 W

V = I × R  →  6 V = 0.6 A × 10 Ω

Voltage
6 V
Current
0.6 A
Resistance
10 Ω
Power (P = V × I)
3.6 W

Voltage 6 volts, current 0.6 amps, resistance 10 ohms, power 3.6 watts. Solving for current.

What Ohm’s law says

Ohm’s law is the workhorse equation of every electric circuit. It ties three quantities together:

V = I × R

Because the three are linked, knowing any two pins down the third. Rearranging the same equation gives I = V ÷ R and R = V ÷ I. Use the “Solve for” buttons in the widget to pick which one you want the circuit to compute, then drag the two sliders and watch the answer update instantly.

Power and the glowing bulb

Voltage and current together set the electrical power a component uses:

P = V × I (in watts, W)

Power is the rate at which electrical energy is converted into other forms — heat and light in a bulb, motion in a motor. In the interactive, the light bulb’s glow brightens as the power rises, so you can see the difference between a dim, low-power circuit and a bright, high-power one. Try holding the resistance steady and raising the voltage: current climbs, and the bulb gets noticeably brighter because power grows with the square of the voltage when resistance is fixed.

A worked example

With V = 6 V and R = 10 Ω, current is I = 6 ÷ 10 = 0.6 A, and the power is P = 6 × 0.6 = 3.6 W. Double the voltage to 12 V (same resistance) and the current doubles to 1.2 A while the power quadruples to 14.4 W — a great way to show students why high-power devices draw so much.

Using this with a class

Project the widget and call out a target — “make the bulb as bright as you can with the resistance fixed at 20 Ω” — or give two values and have students predict the third before they release the slider. It’s free to embed on a class site or LMS page.

Sources

Last reviewed: 2026-06-19

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